Optimal. Leaf size=287 \[ -\frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^3 b^2 d}+\frac{4 \left (-3 a^2 b^4+a^6+2 b^6\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^5 b^2 d \sqrt{a^2-b^2}}+\frac{3 \left (a^2-b^2\right ) \cot (c+d x)}{a^4 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}+\frac{b \tanh ^{-1}(\cos (c+d x))}{a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\cot ^3(c+d x)}{3 a^2 d}-\frac{\cot (c+d x)}{a^2 d}-\frac{x}{b^2} \]
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Rubi [A] time = 0.376761, antiderivative size = 287, normalized size of antiderivative = 1., number of steps used = 17, number of rules used = 10, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.345, Rules used = {2897, 3770, 3767, 8, 3768, 2664, 12, 2660, 618, 204} \[ -\frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^3 b^2 d}+\frac{4 \left (-3 a^2 b^4+a^6+2 b^6\right ) \tan ^{-1}\left (\frac{a \tan \left (\frac{1}{2} (c+d x)\right )+b}{\sqrt{a^2-b^2}}\right )}{a^5 b^2 d \sqrt{a^2-b^2}}+\frac{3 \left (a^2-b^2\right ) \cot (c+d x)}{a^4 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}+\frac{b \tanh ^{-1}(\cos (c+d x))}{a^3 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\cot ^3(c+d x)}{3 a^2 d}-\frac{\cot (c+d x)}{a^2 d}-\frac{x}{b^2} \]
Antiderivative was successfully verified.
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Rule 2897
Rule 3770
Rule 3767
Rule 8
Rule 3768
Rule 2664
Rule 12
Rule 2660
Rule 618
Rule 204
Rubi steps
\begin{align*} \int \frac{\cos ^2(c+d x) \cot ^4(c+d x)}{(a+b \sin (c+d x))^2} \, dx &=\int \left (-\frac{1}{b^2}+\frac{2 \left (3 a^2 b-2 b^3\right ) \csc (c+d x)}{a^5}-\frac{3 \left (a^2-b^2\right ) \csc ^2(c+d x)}{a^4}-\frac{2 b \csc ^3(c+d x)}{a^3}+\frac{\csc ^4(c+d x)}{a^2}-\frac{\left (a^2-b^2\right )^3}{a^4 b^2 (a+b \sin (c+d x))^2}+\frac{2 \left (a^6-3 a^2 b^4+2 b^6\right )}{a^5 b^2 (a+b \sin (c+d x))}\right ) \, dx\\ &=-\frac{x}{b^2}+\frac{\int \csc ^4(c+d x) \, dx}{a^2}-\frac{(2 b) \int \csc ^3(c+d x) \, dx}{a^3}+\frac{\left (2 b \left (3 a^2-2 b^2\right )\right ) \int \csc (c+d x) \, dx}{a^5}-\frac{\left (3 \left (a^2-b^2\right )\right ) \int \csc ^2(c+d x) \, dx}{a^4}-\frac{\left (a^2-b^2\right )^3 \int \frac{1}{(a+b \sin (c+d x))^2} \, dx}{a^4 b^2}+\frac{\left (2 \left (a^6-3 a^2 b^4+2 b^6\right )\right ) \int \frac{1}{a+b \sin (c+d x)} \, dx}{a^5 b^2}\\ &=-\frac{x}{b^2}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}-\frac{b \int \csc (c+d x) \, dx}{a^3}-\frac{\left (a^2-b^2\right )^2 \int \frac{a}{a+b \sin (c+d x)} \, dx}{a^4 b^2}-\frac{\operatorname{Subst}\left (\int \left (1+x^2\right ) \, dx,x,\cot (c+d x)\right )}{a^2 d}+\frac{\left (3 \left (a^2-b^2\right )\right ) \operatorname{Subst}(\int 1 \, dx,x,\cot (c+d x))}{a^4 d}+\frac{\left (4 \left (a^6-3 a^2 b^4+2 b^6\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^5 b^2 d}\\ &=-\frac{x}{b^2}+\frac{b \tanh ^{-1}(\cos (c+d x))}{a^3 d}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}-\frac{\cot (c+d x)}{a^2 d}+\frac{3 \left (a^2-b^2\right ) \cot (c+d x)}{a^4 d}-\frac{\cot ^3(c+d x)}{3 a^2 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}-\frac{\left (a^2-b^2\right )^2 \int \frac{1}{a+b \sin (c+d x)} \, dx}{a^3 b^2}-\frac{\left (8 \left (a^6-3 a^2 b^4+2 b^6\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^5 b^2 d}\\ &=-\frac{x}{b^2}+\frac{4 \left (a^6-3 a^2 b^4+2 b^6\right ) \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{a^5 b^2 \sqrt{a^2-b^2} d}+\frac{b \tanh ^{-1}(\cos (c+d x))}{a^3 d}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}-\frac{\cot (c+d x)}{a^2 d}+\frac{3 \left (a^2-b^2\right ) \cot (c+d x)}{a^4 d}-\frac{\cot ^3(c+d x)}{3 a^2 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}-\frac{\left (2 \left (a^2-b^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{a+2 b x+a x^2} \, dx,x,\tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^3 b^2 d}\\ &=-\frac{x}{b^2}+\frac{4 \left (a^6-3 a^2 b^4+2 b^6\right ) \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{a^5 b^2 \sqrt{a^2-b^2} d}+\frac{b \tanh ^{-1}(\cos (c+d x))}{a^3 d}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}-\frac{\cot (c+d x)}{a^2 d}+\frac{3 \left (a^2-b^2\right ) \cot (c+d x)}{a^4 d}-\frac{\cot ^3(c+d x)}{3 a^2 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}+\frac{\left (4 \left (a^2-b^2\right )^2\right ) \operatorname{Subst}\left (\int \frac{1}{-4 \left (a^2-b^2\right )-x^2} \, dx,x,2 b+2 a \tan \left (\frac{1}{2} (c+d x)\right )\right )}{a^3 b^2 d}\\ &=-\frac{x}{b^2}-\frac{2 \left (a^2-b^2\right )^{3/2} \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{a^3 b^2 d}+\frac{4 \left (a^6-3 a^2 b^4+2 b^6\right ) \tan ^{-1}\left (\frac{b+a \tan \left (\frac{1}{2} (c+d x)\right )}{\sqrt{a^2-b^2}}\right )}{a^5 b^2 \sqrt{a^2-b^2} d}+\frac{b \tanh ^{-1}(\cos (c+d x))}{a^3 d}-\frac{2 b \left (3 a^2-2 b^2\right ) \tanh ^{-1}(\cos (c+d x))}{a^5 d}-\frac{\cot (c+d x)}{a^2 d}+\frac{3 \left (a^2-b^2\right ) \cot (c+d x)}{a^4 d}-\frac{\cot ^3(c+d x)}{3 a^2 d}+\frac{b \cot (c+d x) \csc (c+d x)}{a^3 d}-\frac{\left (a^2-b^2\right )^2 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}\\ \end{align*}
Mathematica [A] time = 6.27399, size = 428, normalized size = 1.49 \[ \frac{\left (5 a^2 b-4 b^3\right ) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )\right )}{a^5 d}+\frac{\left (4 b^3-5 a^2 b\right ) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )\right )}{a^5 d}+\frac{2 a^2 b^2 \cos (c+d x)+a^4 (-\cos (c+d x))-b^4 \cos (c+d x)}{a^4 b d (a+b \sin (c+d x))}+\frac{\csc \left (\frac{1}{2} (c+d x)\right ) \left (7 a^2 \cos \left (\frac{1}{2} (c+d x)\right )-9 b^2 \cos \left (\frac{1}{2} (c+d x)\right )\right )}{6 a^4 d}+\frac{\sec \left (\frac{1}{2} (c+d x)\right ) \left (9 b^2 \sin \left (\frac{1}{2} (c+d x)\right )-7 a^2 \sin \left (\frac{1}{2} (c+d x)\right )\right )}{6 a^4 d}+\frac{2 \left (a^2-b^2\right )^{3/2} \left (a^2+4 b^2\right ) \tan ^{-1}\left (\frac{\sec \left (\frac{1}{2} (c+d x)\right ) \left (a \sin \left (\frac{1}{2} (c+d x)\right )+b \cos \left (\frac{1}{2} (c+d x)\right )\right )}{\sqrt{a^2-b^2}}\right )}{a^5 b^2 d}+\frac{b \csc ^2\left (\frac{1}{2} (c+d x)\right )}{4 a^3 d}-\frac{b \sec ^2\left (\frac{1}{2} (c+d x)\right )}{4 a^3 d}-\frac{\cot \left (\frac{1}{2} (c+d x)\right ) \csc ^2\left (\frac{1}{2} (c+d x)\right )}{24 a^2 d}+\frac{\tan \left (\frac{1}{2} (c+d x)\right ) \sec ^2\left (\frac{1}{2} (c+d x)\right )}{24 a^2 d}-\frac{c+d x}{b^2 d} \]
Warning: Unable to verify antiderivative.
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Maple [B] time = 0.19, size = 678, normalized size = 2.4 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 4.75213, size = 3244, normalized size = 11.3 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27628, size = 539, normalized size = 1.88 \begin{align*} -\frac{\frac{24 \,{\left (d x + c\right )}}{b^{2}} - \frac{24 \,{\left (5 \, a^{2} b - 4 \, b^{3}\right )} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) \right |}\right )}{a^{5}} - \frac{a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 6 \, a^{3} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 27 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 36 \, a^{2} b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )}{a^{6}} - \frac{48 \,{\left (a^{6} + 2 \, a^{4} b^{2} - 7 \, a^{2} b^{4} + 4 \, b^{6}\right )}{\left (\pi \left \lfloor \frac{d x + c}{2 \, \pi } + \frac{1}{2} \right \rfloor \mathrm{sgn}\left (a\right ) + \arctan \left (\frac{a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + b}{\sqrt{a^{2} - b^{2}}}\right )\right )}}{\sqrt{a^{2} - b^{2}} a^{5} b^{2}} + \frac{48 \,{\left (a^{4} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 2 \, a^{2} b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + b^{5} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a^{5} - 2 \, a^{3} b^{2} + a b^{4}\right )}}{{\left (a \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 2 \, b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a\right )} a^{5} b} + \frac{220 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 176 \, b^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} - 27 \, a^{3} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 36 \, a b^{2} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 6 \, a^{2} b \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + a^{3}}{a^{5} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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